Dear Virginie Dujols

I don't know about the synthesis, but it what you're describing is
poly(methacrylic acid).

propylene: H2C=CH-CH3 --> PP: [-H2C-CH(CH3)-]n
acrylic acid: H2C=CHCOOH --> PAA: [-H2C-CH(COOH)-]n
methacrylate: H2C=C(CH3)COOCH3 --> PMMA: [-H2C-C(CH3)(COOCH3)-]n
methacrylic acid: H2C=C(CH3)COOH --> PMAA: [-H2C-C(CH3)COOH)-]n

Both the poly(acrylic acid) and the poly(methacrylic acid) have dangling
COOH groups and are sold by Aldrich. The former is sold as a solid in
various molecular weights and in aqueous solution (with a choice of
acid, sodium, and potassium forms); the latter is sold as an aqueous
sodium salt solution.

Regards,

Chris

On Wednesday, August 28, 2002, at 06:53  am, Virginie Dujols wrote:

> I need to either make -or buy- a PP film with its methyl groups being
> converted into COOH groups. Maybe that would be a PMMA film? I am not
> very
> familiar with polymers! I am an organic chemist and can do traditional
> organic chemistry.
--
Christopher F. Blanford
Inorganic Chemistry Laboratory, South Parks Road, Oxford, OX1 3QR, UK
Phone: (44)/(0)-1865-282603; Fax: (44)/(0)-1865-272690
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